HJKL is a rhombus. HLM is an equilateral triangle. Find
- ∠MHJ
- ∠HJL
(a)
∠MHL
= 180° ÷ 3
= 60° (Equilateral triangle)
∠JHL = ∠JKL = 108° (Rhombus)
∠MHJ
= 108° + 60°
= 168°
(b)
∠HJL
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
Answer(s): (a) 168°; (b) 36°