BCDE is a rhombus. BEF is an equilateral triangle. Find
- ∠FBC
- ∠BCE
(a)
∠FBE
= 180° ÷ 3
= 60° (Equilateral triangle)
∠CBE = ∠CDE = 108° (Rhombus)
∠FBC
= 108° + 60°
= 168°
(b)
∠BCE
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
Answer(s): (a) 168°; (b) 36°