DEFG is a rhombus. DGH is an equilateral triangle. Find
- ∠HDE
- ∠DEG
(a)
∠HDG
= 180° ÷ 3
= 60° (Equilateral triangle)
∠EDG = ∠EFG = 108° (Rhombus)
∠HDE
= 108° + 60°
= 168°
(b)
∠DEG
= (180° - 108°) ÷ 2
= 36° (Isosceles triangle)
Answer(s): (a) 168°; (b) 36°