In the diagram shown, NPQ is a right-angled triangle and NP = PQ = NR. Find
- ∠RNQ
- ∠NRP
(a)
∠NQP
= (180° - 90°) ÷ 2
= 45° (Isosceles triangle)
∠RNQ
= 45° - 33°
= 12°
(b)
∠NRP
= (180° - 33°) ÷ 2
= 73.5° (Isosceles triangle)
Answer(s): (a) 12°; (b) 73.5°