In the diagram shown, EFG is a right-angled triangle and EF = FG = EH. Find
- ∠HEG
- ∠EHF
(a)
∠EGF
= (180° - 90°) ÷ 2
= 45° (Isosceles triangle)
∠HEG
= 45° - 29°
= 16°
(b)
∠EHF
= (180° - 29°) ÷ 2
= 75.5° (Isosceles triangle)
Answer(s): (a) 16°; (b) 75.5°