In the diagram shown, CDE is a right-angled triangle and CD = DE = CF. Find
- ∠FCE
- ∠CFD
(a)
∠CED
= (180° - 90°) ÷ 2
= 45° (Isosceles triangle)
∠FCE
= 45° - 29°
= 16°
(b)
∠CFD
= (180° - 29°) ÷ 2
= 75.5° (Isosceles triangle)
Answer(s): (a) 16°; (b) 75.5°