In the diagram shown, ABC is a right-angled triangle and AB = BC = AD. Find
- ∠DAC
- ∠ADB
(a)
∠ACB
= (180° - 90°) ÷ 2
= 45° (Isosceles triangle)
∠DAC
= 45° - 29°
= 16°
(b)
∠ADB
= (180° - 29°) ÷ 2
= 75.5° (Isosceles triangle)
Answer(s): (a) 16°; (b) 75.5°