In the figure, RS = RU, ∠SRU = 32° and ∠VTU = 16°. Find
- ∠v
- ∠w
(a)
∠RSU
= (180° - 32°) ÷ 2
= 74° (Isosceles triangle)
∠v
= 180° - 16° - 74°
= 90° (Angles sum of triangle)
(b)
∠RUT
= 180° - 74°
= 106° (Angles on a straight line)
∠w
= 16° + 106°
= 122° (Exterior angle of a triangle)
Answer(s): (a) 90°; (b) 122°