In the figure, TU = TW, ∠UTW = 35° and ∠XVW = 12°. Find
- ∠f
- ∠g
(a)
∠TUW
= (180° - 35°) ÷ 2
= 72.5° (Isosceles triangle)
∠f
= 180° - 12° - 72.5°
= 95.5° (Angles sum of triangle)
(b)
∠TWV
= 180° - 72.5°
= 107.5° (Angles on a straight line)
∠g
= 12° + 107.5°
= 119.5° (Exterior angle of a triangle)
Answer(s): (a) 95.5°; (b) 119.5°