In the figure, QR = QT, ∠RQT = 32° and ∠UST = 18°. Find
- ∠m
- ∠n
(a)
∠QRT
= (180° - 32°) ÷ 2
= 74° (Isosceles triangle)
∠m
= 180° - 18° - 74°
= 88° (Angles sum of triangle)
(b)
∠QTS
= 180° - 74°
= 106° (Angles on a straight line)
∠n
= 18° + 106°
= 124° (Exterior angle of a triangle)
Answer(s): (a) 88°; (b) 124°