In the figure, EF = EH, ∠FEH = 34° and ∠JGH = 17°. Find
- ∠y
- ∠z
(a)
∠EFH
= (180° - 34°) ÷ 2
= 73° (Isosceles triangle)
∠y
= 180° - 17° - 73°
= 90° (Angles sum of triangle)
(b)
∠EHG
= 180° - 73°
= 107° (Angles on a straight line)
∠z
= 17° + 107°
= 124° (Exterior angle of a triangle)
Answer(s): (a) 90°; (b) 124°