In the figure, MN = MQ, ∠NMQ = 37° and ∠RPQ = 16°. Find
- ∠t
- ∠v
(a)
∠MNQ
= (180° - 37°) ÷ 2
= 71.5° (Isosceles triangle)
∠t
= 180° - 16° - 71.5°
= 92.5° (Angles sum of triangle)
(b)
∠MQP
= 180° - 71.5°
= 108.5° (Angles on a straight line)
∠v
= 16° + 108.5°
= 124.5° (Exterior angle of a triangle)
Answer(s): (a) 92.5°; (b) 124.5°