In the figure, RS = RU, ∠SRU = 35° and ∠VTU = 17°. Find
- ∠m
- ∠n
(a)
∠RSU
= (180° - 35°) ÷ 2
= 72.5° (Isosceles triangle)
∠m
= 180° - 17° - 72.5°
= 90.5° (Angles sum of triangle)
(b)
∠RUT
= 180° - 72.5°
= 107.5° (Angles on a straight line)
∠n
= 17° + 107.5°
= 124.5° (Exterior angle of a triangle)
Answer(s): (a) 90.5°; (b) 124.5°
