In the figure, QR = QT, ∠RQT = 36° and ∠UST = 13°. Find
- ∠v
- ∠w
(a)
∠QRT
= (180° - 36°) ÷ 2
= 72° (Isosceles triangle)
∠v
= 180° - 13° - 72°
= 95° (Angles sum of triangle)
(b)
∠QTS
= 180° - 72°
= 108° (Angles on a straight line)
∠w
= 13° + 108°
= 121° (Exterior angle of a triangle)
Answer(s): (a) 95°; (b) 121°