In the figure, GH = GK, ∠HGK = 36° and ∠LJK = 12°. Find
- ∠y
- ∠z
(a)
∠GHK
= (180° - 36°) ÷ 2
= 72° (Isosceles triangle)
∠y
= 180° - 12° - 72°
= 96° (Angles sum of triangle)
(b)
∠GKJ
= 180° - 72°
= 108° (Angles on a straight line)
∠z
= 12° + 108°
= 120° (Exterior angle of a triangle)
Answer(s): (a) 96°; (b) 120°