In the figure, LM = LP, ∠MLP = 37° and ∠QNP = 18°. Find
- ∠h
- ∠i
(a)
∠LMP
= (180° - 37°) ÷ 2
= 71.5° (Isosceles triangle)
∠h
= 180° - 18° - 71.5°
= 90.5° (Angles sum of triangle)
(b)
∠LPN
= 180° - 71.5°
= 108.5° (Angles on a straight line)
∠i
= 18° + 108.5°
= 126.5° (Exterior angle of a triangle)
Answer(s): (a) 90.5°; (b) 126.5°