In the figure, HJ = HL, ∠JHL = 34° and ∠MKL = 13°. Find
- ∠s
- ∠t
(a)
∠HJL
= (180° - 34°) ÷ 2
= 73° (Isosceles triangle)
∠s
= 180° - 13° - 73°
= 94° (Angles sum of triangle)
(b)
∠HLK
= 180° - 73°
= 107° (Angles on a straight line)
∠t
= 13° + 107°
= 120° (Exterior angle of a triangle)
Answer(s): (a) 94°; (b) 120°