In the figure, GH = GK, ∠HGK = 34° and ∠LJK = 13°. Find
- ∠q
- ∠r
(a)
∠GHK
= (180° - 34°) ÷ 2
= 73° (Isosceles triangle)
∠q
= 180° - 13° - 73°
= 94° (Angles sum of triangle)
(b)
∠GKJ
= 180° - 73°
= 107° (Angles on a straight line)
∠r
= 13° + 107°
= 120° (Exterior angle of a triangle)
Answer(s): (a) 94°; (b) 120°