In the figure, TU = TW, ∠UTW = 34° and ∠XVW = 14°. Find
- ∠p
- ∠q
(a)
∠TUW
= (180° - 34°) ÷ 2
= 73° (Isosceles triangle)
∠p
= 180° - 14° - 73°
= 93° (Angles sum of triangle)
(b)
∠TWV
= 180° - 73°
= 107° (Angles on a straight line)
∠q
= 14° + 107°
= 121° (Exterior angle of a triangle)
Answer(s): (a) 93°; (b) 121°