In the figure, BC = BE, ∠CBE = 36° and ∠FDE = 12°. Find
- ∠w
- ∠x
(a)
∠BCE
= (180° - 36°) ÷ 2
= 72° (Isosceles triangle)
∠w
= 180° - 12° - 72°
= 96° (Angles sum of triangle)
(b)
∠BED
= 180° - 72°
= 108° (Angles on a straight line)
∠x
= 12° + 108°
= 120° (Exterior angle of a triangle)
Answer(s): (a) 96°; (b) 120°