In the figure, GH = GK, ∠HGK = 32° and ∠LJK = 18°. Find
- ∠e
- ∠f
(a)
∠GHK
= (180° - 32°) ÷ 2
= 74° (Isosceles triangle)
∠e
= 180° - 18° - 74°
= 88° (Angles sum of triangle)
(b)
∠GKJ
= 180° - 74°
= 106° (Angles on a straight line)
∠f
= 18° + 106°
= 124° (Exterior angle of a triangle)
Answer(s): (a) 88°; (b) 124°