In the figure, JK = JM, ∠KJM = 32° and ∠NLM = 17°. Find
- ∠j
- ∠k
(a)
∠JKM
= (180° - 32°) ÷ 2
= 74° (Isosceles triangle)
∠j
= 180° - 17° - 74°
= 89° (Angles sum of triangle)
(b)
∠JML
= 180° - 74°
= 106° (Angles on a straight line)
∠k
= 17° + 106°
= 123° (Exterior angle of a triangle)
Answer(s): (a) 89°; (b) 123°