In the figure, ST = SV, ∠TSV = 33° and ∠WUV = 12°. Find
- ∠w
- ∠x
(a)
∠STV
= (180° - 33°) ÷ 2
= 73.5° (Isosceles triangle)
∠w
= 180° - 12° - 73.5°
= 94.5° (Angles sum of triangle)
(b)
∠SVU
= 180° - 73.5°
= 106.5° (Angles on a straight line)
∠x
= 12° + 106.5°
= 118.5° (Exterior angle of a triangle)
Answer(s): (a) 94.5°; (b) 118.5°