In the figure, KL = KN, ∠LKN = 35° and ∠PMN = 17°. Find
- ∠b
- ∠c
(a)
∠KLN
= (180° - 35°) ÷ 2
= 72.5° (Isosceles triangle)
∠b
= 180° - 17° - 72.5°
= 90.5° (Angles sum of triangle)
(b)
∠KNM
= 180° - 72.5°
= 107.5° (Angles on a straight line)
∠c
= 17° + 107.5°
= 124.5° (Exterior angle of a triangle)
Answer(s): (a) 90.5°; (b) 124.5°