In the figure, RS = RU, ∠SRU = 32° and ∠VTU = 15°. Find
- ∠p
- ∠q
(a)
∠RSU
= (180° - 32°) ÷ 2
= 74° (Isosceles triangle)
∠p
= 180° - 15° - 74°
= 91° (Angles sum of triangle)
(b)
∠RUT
= 180° - 74°
= 106° (Angles on a straight line)
∠q
= 15° + 106°
= 121° (Exterior angle of a triangle)
Answer(s): (a) 91°; (b) 121°