In the figure, JK = JM, ∠KJM = 37° and ∠NLM = 14°. Find
- ∠v
- ∠w
(a)
∠JKM
= (180° - 37°) ÷ 2
= 71.5° (Isosceles triangle)
∠v
= 180° - 14° - 71.5°
= 94.5° (Angles sum of triangle)
(b)
∠JML
= 180° - 71.5°
= 108.5° (Angles on a straight line)
∠w
= 14° + 108.5°
= 122.5° (Exterior angle of a triangle)
Answer(s): (a) 94.5°; (b) 122.5°