In the figure, DE = DG, ∠EDG = 37° and ∠HFG = 12°. Find
- ∠y
- ∠z
(a)
∠DEG
= (180° - 37°) ÷ 2
= 71.5° (Isosceles triangle)
∠y
= 180° - 12° - 71.5°
= 96.5° (Angles sum of triangle)
(b)
∠DGF
= 180° - 71.5°
= 108.5° (Angles on a straight line)
∠z
= 12° + 108.5°
= 120.5° (Exterior angle of a triangle)
Answer(s): (a) 96.5°; (b) 120.5°