In the figure, KL = KN, ∠LKN = 34° and ∠PMN = 15°. Find
- ∠r
- ∠s
(a)
∠KLN
= (180° - 34°) ÷ 2
= 73° (Isosceles triangle)
∠r
= 180° - 15° - 73°
= 92° (Angles sum of triangle)
(b)
∠KNM
= 180° - 73°
= 107° (Angles on a straight line)
∠s
= 15° + 107°
= 122° (Exterior angle of a triangle)
Answer(s): (a) 92°; (b) 122°