In the figure, GH = GK, ∠HGK = 37° and ∠LJK = 15°. Find
- ∠e
- ∠f
(a)
∠GHK
= (180° - 37°) ÷ 2
= 71.5° (Isosceles triangle)
∠e
= 180° - 15° - 71.5°
= 93.5° (Angles sum of triangle)
(b)
∠GKJ
= 180° - 71.5°
= 108.5° (Angles on a straight line)
∠f
= 15° + 108.5°
= 123.5° (Exterior angle of a triangle)
Answer(s): (a) 93.5°; (b) 123.5°