In the figure, KL = KN, ∠LKN = 37° and ∠PMN = 14°. Find
- ∠j
- ∠k
(a)
∠KLN
= (180° - 37°) ÷ 2
= 71.5° (Isosceles triangle)
∠j
= 180° - 14° - 71.5°
= 94.5° (Angles sum of triangle)
(b)
∠KNM
= 180° - 71.5°
= 108.5° (Angles on a straight line)
∠k
= 14° + 108.5°
= 122.5° (Exterior angle of a triangle)
Answer(s): (a) 94.5°; (b) 122.5°