In the figure, QR = QT, ∠RQT = 31° and ∠UST = 14°. Find
- ∠x
- ∠y
(a)
∠QRT
= (180° - 31°) ÷ 2
= 74.5° (Isosceles triangle)
∠x
= 180° - 14° - 74.5°
= 91.5° (Angles sum of triangle)
(b)
∠QTS
= 180° - 74.5°
= 105.5° (Angles on a straight line)
∠y
= 14° + 105.5°
= 119.5° (Exterior angle of a triangle)
Answer(s): (a) 91.5°; (b) 119.5°