In the figure, QR = QT, ∠RQT = 33° and ∠UST = 14°. Find
- ∠f
- ∠g
(a)
∠QRT
= (180° - 33°) ÷ 2
= 73.5° (Isosceles triangle)
∠f
= 180° - 14° - 73.5°
= 92.5° (Angles sum of triangle)
(b)
∠QTS
= 180° - 73.5°
= 106.5° (Angles on a straight line)
∠g
= 14° + 106.5°
= 120.5° (Exterior angle of a triangle)
Answer(s): (a) 92.5°; (b) 120.5°