In the figure, LM = LP, ∠MLP = 33° and ∠QNP = 13°. Find
- ∠i
- ∠j
(a)
∠LMP
= (180° - 33°) ÷ 2
= 73.5° (Isosceles triangle)
∠i
= 180° - 13° - 73.5°
= 93.5° (Angles sum of triangle)
(b)
∠LPN
= 180° - 73.5°
= 106.5° (Angles on a straight line)
∠j
= 13° + 106.5°
= 119.5° (Exterior angle of a triangle)
Answer(s): (a) 93.5°; (b) 119.5°