In the figure, DE = DG, ∠EDG = 34° and ∠HFG = 13°. Find
- ∠m
- ∠n
(a)
∠DEG
= (180° - 34°) ÷ 2
= 73° (Isosceles triangle)
∠m
= 180° - 13° - 73°
= 94° (Angles sum of triangle)
(b)
∠DGF
= 180° - 73°
= 107° (Angles on a straight line)
∠n
= 13° + 107°
= 120° (Exterior angle of a triangle)
Answer(s): (a) 94°; (b) 120°