In the figure, JK = JM, ∠KJM = 34° and ∠NLM = 18°. Find
- ∠x
- ∠y
(a)
∠JKM
= (180° - 34°) ÷ 2
= 73° (Isosceles triangle)
∠x
= 180° - 18° - 73°
= 89° (Angles sum of triangle)
(b)
∠JML
= 180° - 73°
= 107° (Angles on a straight line)
∠y
= 18° + 107°
= 125° (Exterior angle of a triangle)
Answer(s): (a) 89°; (b) 125°