In the figure, RS = RU, ∠SRU = 36° and ∠VTU = 16°. Find
- ∠t
- ∠v
(a)
∠RSU
= (180° - 36°) ÷ 2
= 72° (Isosceles triangle)
∠t
= 180° - 16° - 72°
= 92° (Angles sum of triangle)
(b)
∠RUT
= 180° - 72°
= 108° (Angles on a straight line)
∠v
= 16° + 108°
= 124° (Exterior angle of a triangle)
Answer(s): (a) 92°; (b) 124°
