Given the figure, find
- ∠q
- ∠p
(a)
∠BCG
= 180° - 131°
= 49° (Angles on a straight line)
∠q = 49° (Alternate angles)
(b)
∠GFC
= 180° - 114°
= 66° (Angles on a straight line)
∠p
= 180° - 66° - 75°
= 39° (Angles sum of triangle)
Answer(s): (a) 49°; (b) 39°