Given the figure, find
- ∠q
- ∠p
(a)
∠KLQ
= 180° - 130°
= 50° (Angles on a straight line)
∠q = 50° (Alternate angles)
(b)
∠QPL
= 180° - 110°
= 70° (Angles on a straight line)
∠p
= 180° - 70° - 77°
= 33° (Angles sum of triangle)
Answer(s): (a) 50°; (b) 33°