GHJK and BCDJ are rhombuses. Find ∠BFH.
∠BHK
= (180° - 119°) ÷ 2
= 30.5° (Isosceles triangle)
∠DCE
= 180° - 90° - 18°
= 72° (Angles sum of triangle)
∠JBH = ∠DCE
= 72° (Corresponding angles)
∠BFH
= 180° - 72° - 30.5°
= 77.5° (Angles sum of triangle)
Answer(s): 77.5°