GHJK and BCDJ are rhombuses. Find ∠BFH.
∠BHK
= (180° - 117°) ÷ 2
= 31.5° (Isosceles triangle)
∠DCE
= 180° - 90° - 14°
= 76° (Angles sum of triangle)
∠JBH = ∠DCE
= 76° (Corresponding angles)
∠BFH
= 180° - 76° - 31.5°
= 72.5° (Angles sum of triangle)
Answer(s): 72.5°