FGHJ and ABCH are rhombuses. Find ∠AEG.
∠AGJ
= (180° - 122°) ÷ 2
= 29° (Isosceles triangle)
∠CBD
= 180° - 90° - 15°
= 75° (Angles sum of triangle)
∠HAG = ∠CBD
= 75° (Corresponding angles)
∠AEG
= 180° - 75° - 29°
= 76° (Angles sum of triangle)
Answer(s): 76°