VWXY and QRSX are rhombuses. Find ∠QUW.
∠QWY
= (180° - 116°) ÷ 2
= 32° (Isosceles triangle)
∠SRT
= 180° - 90° - 17°
= 73° (Angles sum of triangle)
∠XQW = ∠SRT
= 73° (Corresponding angles)
∠QUW
= 180° - 73° - 32°
= 75° (Angles sum of triangle)
Answer(s): 75°