HJKL and CDEK are rhombuses. Find ∠CGJ.
∠CJL
= (180° - 118°) ÷ 2
= 31° (Isosceles triangle)
∠EDF
= 180° - 90° - 14°
= 76° (Angles sum of triangle)
∠KCJ = ∠EDF
= 76° (Corresponding angles)
∠CGJ
= 180° - 76° - 31°
= 73° (Angles sum of triangle)
Answer(s): 73°