JKLM and DEFL are rhombuses. Find ∠DHK.
∠DKM
= (180° - 120°) ÷ 2
= 30° (Isosceles triangle)
∠FEG
= 180° - 90° - 12°
= 78° (Angles sum of triangle)
∠LDK = ∠FEG
= 78° (Corresponding angles)
∠DHK
= 180° - 78° - 30°
= 72° (Angles sum of triangle)
Answer(s): 72°