JKLM and DEFL are rhombuses. Find ∠DHK.
∠DKM
= (180° - 124°) ÷ 2
= 28° (Isosceles triangle)
∠FEG
= 180° - 90° - 13°
= 77° (Angles sum of triangle)
∠LDK = ∠FEG
= 77° (Corresponding angles)
∠DHK
= 180° - 77° - 28°
= 75° (Angles sum of triangle)
Answer(s): 75°