FGHJ and ABCH are rhombuses. Find ∠AEG.
∠AGJ
= (180° - 119°) ÷ 2
= 30.5° (Isosceles triangle)
∠CBD
= 180° - 90° - 14°
= 76° (Angles sum of triangle)
∠HAG = ∠CBD
= 76° (Corresponding angles)
∠AEG
= 180° - 76° - 30.5°
= 73.5° (Angles sum of triangle)
Answer(s): 73.5°