KLMN and EFGM are rhombuses. Find ∠EJL.
∠ELN
= (180° - 124°) ÷ 2
= 28° (Isosceles triangle)
∠GFH
= 180° - 90° - 15°
= 75° (Angles sum of triangle)
∠MEL = ∠GFH
= 75° (Corresponding angles)
∠EJL
= 180° - 75° - 28°
= 77° (Angles sum of triangle)
Answer(s): 77°