VWXY and QRSX are rhombuses. Find ∠QUW.
∠QWY
= (180° - 123°) ÷ 2
= 28.5° (Isosceles triangle)
∠SRT
= 180° - 90° - 14°
= 76° (Angles sum of triangle)
∠XQW = ∠SRT
= 76° (Corresponding angles)
∠QUW
= 180° - 76° - 28.5°
= 75.5° (Angles sum of triangle)
Answer(s): 75.5°