HJKL and CDEK are rhombuses. Find ∠CGJ.
∠CJL
= (180° - 121°) ÷ 2
= 29.5° (Isosceles triangle)
∠EDF
= 180° - 90° - 12°
= 78° (Angles sum of triangle)
∠KCJ = ∠EDF
= 78° (Corresponding angles)
∠CGJ
= 180° - 78° - 29.5°
= 72.5° (Angles sum of triangle)
Answer(s): 72.5°