HJKL and CDEK are rhombuses. Find ∠CGJ.
∠CJL
= (180° - 122°) ÷ 2
= 29° (Isosceles triangle)
∠EDF
= 180° - 90° - 16°
= 74° (Angles sum of triangle)
∠KCJ = ∠EDF
= 74° (Corresponding angles)
∠CGJ
= 180° - 74° - 29°
= 77° (Angles sum of triangle)
Answer(s): 77°